Question

an elevator descends into a mine shaft at the rate of 6m/min. If the descent starts from 10m above the ground level how long will it take to reach -350m deep under the ground​. please help fast Give clear explanation also. Jai shree ram​

Answer 1

Answer:

60 min or 1 hour

Step-by-step explanation:

d = |10 - (- 350)| = 360 m and r = 6 m/min

d = t × r ===> t = d / r

t = 360 / 6 = 60 min. = 1 hour