An elevator descends into a mine shaft at the rate of 6m/min.if the descent starts from 10m above the ground level,how long will it take to reach(-350) m.
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length of the mine shaft =-360
rate of elevator =-360/6
time taken to reach =60minutes
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rate of elevator =-360/6
time taken to reach =60minutes
I hope it will help you. please send thanks for me.
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