an elevator descends into a mine shaft at the rate of 6m/min, If it desends from 20m till -370 below ground what is the time
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Step-by-step explanation:
total distance cover by elevator= 370+ 20 = 390 min
now ,the time that the elevator has to cover with a speed of 6m/min is -390/6 min ,or-65min or 1hour 5mint
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