Math, asked by shaheem70, 8 months ago

An elevator descends into a mine shaft at the rate of 6metre per min . If the descent starts from 10m above the ground level

Answers

Answered by Yashicaruthvik

2

Answer:

speed of the elevator=6 m/min

total distance =350 + 10 =360m(as it starts from 10m above the ground level)

time taken=(360÷6)=60min

or 1hour ans.

Step-by-step explanation:

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