Question

An elevator descends into a mine shaft at the rate of 7 meter per minute what will be it's position after hour

Answer 1

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Here is the solution:

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Rate: 1 min = 7 metre (Given)

Convert hour to min:

1 hour = 60 min

Find change in distance after 60 mins:

1 min = 7 m

60 min = 7 x 60 = 420m

Answer: The elevator will be 420m into a mine shaft after an hour.

Answer 2

Answer:

-420 meters ; Step-By-Step Explanations Below↓

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-Rate at which elevator descends: 7m/min
-Position after 1 hour: (-7) x 60 = -420 meters

ANS: -420 METERS
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WHY? Since the elevator descends at a rate of 7m/min, and owing to the fact that 1 hour has 60 minutes in it, we have to find out how much it moves in an hour. So, by multiplying (-7) x 60, we can find out the elevator's position after an hour. And the answer is -420 meters.