an elevator descends into a mine shaft at the rate of 7 m per minute from a height of 12 m above the ground.what will be its position after 25 minutes
Answers
Answered by
0
the velocity of elevator=7m/min.
height above ground=12metres
after 25 minutes it will cover distance =175m
so it is 163m under the ground
height above ground=12metres
after 25 minutes it will cover distance =175m
so it is 163m under the ground
Similar questions