Math, asked by tilakrajkumar, 11 months ago

An elevator descends into a mine shaft at the rate of 8 m/min. If it starts descending from
5 m above the ground level, how long will it take to reach -195 m?

Answers

Answered by Bhoomi3621

1

Answer:

Step-by-step explanation:

speed=390

time=8min

distance=s×t

390×8=3120

above 10 m ground level=

390-10 =380m

Please mark the answer as brainlist

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