an elevator descends into a mine shaft at the rate of 8 m/min. if the descent starts from 20 metre above ground level how long will it take to reach - 460 m
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Answer:
60 minutes = 1 hour
Step-by-step explanation:
level above ground = 20
level level above the ground = - 460 m
Therefore the total distance = 20 - (-460) m
= 460 + 20 m
= 480 m
speed = 8m/min
we know that time = distance / speed
= (480 / 8)min
= 60 minutes = 1 hour
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