Question

An elevator descends into a mine shaft at the rate of 8 M per minute. if the descends start from 30 m above the ground level, find the time taken by the elevator to reach -270 m.​

Answer 1

Answer:

Step-by-step explanation:

rate=8 m/minute

total distance=30 m above the ground+270 m below the ground.

                       =300 m

therefore time required to reach -270 m

                                       = 300/8

                                       = 37.5 min.

                                        =0.625 hour