Question

An elevator descends into a mine shaft at the rate of 8m/min.If the descents start from 10m above the ground level, how long will it take to reach -350m.

Answer 1

Given :-

• Speed of elevator = 8 m/minute
• Initial height of elevator = 10 m
• Final depth of elevator = -350 m

To Find :-

• Time taken

Solution :-

$\boxed{\boxed{\sf {Total \ distance = Initial \ height + Final \ depth}}}}}}}$

Thus, distance to be descended by elevator = -350 + (-10 ) = -360 m

Time taken by elevator to descend -8 m = 1 minute

Time taken by the elevator to descend -360 m = -360 ÷ (-8)

= 40 minutes

Thus, time = 40 minutes

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

Extra Information :-

✦ The question is from Maths NCERT - Class 7.

✦ The chapter is Lesson - 1 Integers.

✦ This particular objective is from the part Division of Integers.