An elevator descends into a mine shaft at the rate of 9 m per minute.If the descent starts from 20 m above the ground level,how long will it take to reach -250m?
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Total distance = 250+20 (20 m above the ground and 250 below) = 270
Speed = 9 m/p
T = d/s, = 270/9 = 30 minutes
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