Question

An elevator descends into a mine shraft at the rate of 6 m/min .If the descend starts from 10m above the ground level,how long will it take to reach the shaft 350m below the ground level?

​

Answer 1

Answer:

I think your answer should be 60 minutes.

That’s because it’s 10 meters above ground and needs to go 350 meters below.

So, we add 10 + 350 = 360 meters

When we divide 360 by 6, we get 60.

Thus, your answer should be 60 minutes.

I hope I have helped!

Answer 2

Answer:

Step-by-step explanation:

Given,

• An elevator descends into a mine shrift at the rate of 6 m/min.
• If the descend starts from 10m above the ground level.

Solution,

Total distance elevator has travel = (Initial - final) position.

Total distance elevator has travel = 10 - (- 350)

Total distance elevator has travel = 10 + 350

Total distance elevator has travel = 360 m.

Elevator travels in 6 m in 1 min,

= 1/6 minute

= 1/6 × 360 minute

= 1 hour.

Hence, it take to reach the shaft 350m below the ground level in 1 hour.