An elevator descends into mine shaft at the rate of 6m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350.
Answers
Answered by
26
1 hour or 60 minutes
Answered by
54
Answer:
Time = 1 hour
Step-by-step explanation:
An elevator descends into mine shaft at the rate of 6 m/min
⇒ In every minute, elevator goes down by 6 m
We have 10 m above the ground and 350 m below the ground level
Note : -350 m, means it is 350 m below the ground level
Total distance to be covered by the elevator = 10 + 350
= 360 m
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