Math, asked by matiurrahman440, 1 year ago

An elevator descends into mine shaft at the rate of 6m/min. If the descent starts from 10 m above the ground level, how long will it take to reach -350.

Answers

Answered by sivi1629
26
1 hour or 60 minutes
Answered by throwdolbeau
54

Answer:

Time = 1 hour

Step-by-step explanation:

An elevator descends into mine shaft at the rate of 6 m/min

⇒ In every minute, elevator goes down by 6 m

We have 10 m above the ground and 350 m below the ground level

Note : -350 m, means it is 350 m below the ground level

Total distance to be covered by the elevator = 10 + 350

                                                                           = 360 m

\textbf{Time taken = }\frac{\textbf{Distance to be covered}}{\textbf{Speed}}\\\\\bf\implies Time=\frac{360}{6}\\\\\implies Time = 60\textbf{ minutes or 1 hour}

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