Math, asked by mathematics8, 1 year ago

an elevator descends into underground shaft at the rate of 7m/min.if the descent starts from 15m above the ground level,how long will it take to reach -475m?

Answers

Answered by h15

The ground level is 0 then total distance that elevator will cover
== 475+15 == 490m
Speed of elevator == 7m/min
So time taken to cover 490m == =490/7 = 70min or 1hr 10 min

HOPE THIS HELPS YOU! ! !

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