Question

an elevator descends to a mine shaft art the rate of 19/4 meter per minute if it begins to descend from 15/2 m above the ground what will be it's position after 18 minutes from the ground proper explanation​

Answer 1

Answer:

-78 m

Step-by-step explanation:

As known, Distance= Speed * time

So in 18 min the elevator would travel on 19/4 *18 = 171/2 m

Now the elevator starts from 15/2 meter So the the position would be, 15/2 - 171/2 = 156/2 = -78 m