Math, asked by khushilm2007, 11 months ago

An elevator descents into a mine shaft at the rate of 6 m/min. If the decent starts from 10 m above the ground level, how long will it take to reach -350 m ?

A)10 mins
B)20 mins
C)1 hour
D)45 min

Pls give the solution. With the ans.

Answers

Answered by shashwat763615
2

Answer:

Correct Answer = C)1 hour

Attachments:
Answered by EagOp
5

Answer:

c) 1 Hour

Step-by-step explanation:

Rate= -6m/min

Total distance covered = 10 - (-350)

= 360 m

Time = Distance

Rate

= 360

6m/min

= 360

6 min

60 min = 1 hour

Total time = 1 hour or 60 min

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