An elevator descents into a mine shaft at the rate of 6 m/min. If the decent starts from 10 m above the ground level, how long will it take to reach -350 m ?
A)10 mins
B)20 mins
C)1 hour
D)45 min
Pls give the solution. With the ans.
Answers
Answered by
2
Answer:
Correct Answer = C)1 hour
Attachments:
Answered by
5
Answer:
c) 1 Hour
Step-by-step explanation:
Rate= -6m/min
Total distance covered = 10 - (-350)
= 360 m
Time = Distance
Rate
= 360
6m/min
= 360
6 min
60 min = 1 hour
Total time = 1 hour or 60 min
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