Math, asked by AryanSingh970, 9 months ago

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Answered by sangeeta7701
1

Answer:

Step-by-step explanation:

On taking denominator as common and say theta =x we get,

(sin^3x+cos^3x+sin^2xcosx+cos^2xsinx)/(sinx+cosx)

We know,

sin^3x+cos^3x=1-sinxcosx

=(1-sinxcosx +sinxcosx(sinx+cosx)) /(sinx+cosx)

=(1+sinxcosx(sinx+cosx-1))/(sinx+cosx)

Now you can solve it

Hope it helps you :-)

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