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Step-by-step explanation:
On taking denominator as common and say theta =x we get,
(sin^3x+cos^3x+sin^2xcosx+cos^2xsinx)/(sinx+cosx)
We know,
sin^3x+cos^3x=1-sinxcosx
=(1-sinxcosx +sinxcosx(sinx+cosx)) /(sinx+cosx)
=(1+sinxcosx(sinx+cosx-1))/(sinx+cosx)
Now you can solve it
Hope it helps you :-)
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