Question

an elevator descents into a mine shaft at the rate of 6m/min.if the descent starts from 10m above the ground level, how long will it take to reach -350m​

Answer 1

Answer:

Step-by-step explanation:

to solve this type of questions draw the diagram first i don't know how to draw here so i am not drawing it

now in the question they used the word desents means opposite direction

so u=-6 m/min

convert min into seconds

now u=1/10 m/sec

now the elevator is 10 m above ground level

now total distance it travelled is 360 m

now use the formula

S=UT+(1/2)gT2

now it is a quadratic equation solve it

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