Math, asked by thakurshaurya, 1 year ago

An elevator desends into a mine shaft at the rate of 6m\min . If the desent starts from 10m above the ground level,how long will it take to reach -350

Answers

Answered by aachi2
12
speed of mine sharft =6m/min
total vertical distance = 10+350
=360m
time = distance /speed
360m/ 6m per hour
=60min or 1 hour
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