Question

An elevator is 25m below the ground level and it ascends at the rate of 5m/min.Find the time taken by it to reach 50m above the ground.

Answer 1

Answer:

The elevator had top totally travel a distance of:

$50 - ( - 25) \\ = 75m$

The time the elevator takes top travel 75m is:

$\frac{length}{speed} \\ = 75 \div 5 \\ = \frac{75}{5} \\ = 15 \: mins$

Hope this helps.

Thanks.