Question

An elevator is moving upward with a constant speed of 10 m/s. A man standing in the elevator drops a coin from a height of 25 m, the coin reaches
the floor of the elevator after a time g = 10 m/s
10 m/s² sec. Then N =
/
​

Answer 1

Lift frame :

Initial speed of the coin u=0 m/s

Acceleration a=9.8 m/s

2

Initial height of coin from the floor of elevator h=2.45 m

Time taken by coin to hit the floor T=

g

2H

⟹ T=

9.8

2×2.45

=

2

1

s