Question

An elevator moving downward at 4.0 m/s experiences and upward acceleration of 2.00 m/s^2 for 1.80 seconds. What is the velocity at the end of the acceleration and how fas has it traveled

Answer 1

Explanation:

v=u+at

v=4+(-2)1.80 since a=opposite direction

v=4-3.6

v=0.4m/s

s=ut+1/2at^2

s=4×1.80+1/2×-2×1.80×1.80

s=7.2-3.24

s=3.96

Answer 2

Answer:

v = 0.4m/s, s = 3.96

Explanation:

v = u+at

u = +4 m/s

a = -2/s (an it's in opposite direction of motion )

t = 1.80 second

= 4+(-2)×1.80

= 4-3.6

= 0.4

s = ut+1/2at²

= 4×1.80+1/2(-2)×(1.80)²

=7.2-3.24

= 3.96