Question

an employ got rs200 per month in his 11th year service and got rs495 per month in his 24th year of service if is monthly salary is ap that what is his initial salary what is his increments
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Answer 1

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Answer 2

Concept

The difference between every two successive terms in a sequence is the same; this is known as an arithmetic progression (AP). It is possible to obtain a formula for the nth term of the AP using this kind of development. A good example of an arithmetic progression (AP) is the series 2, 6, 10, 14,..., which follows a pattern in which each number is created by adding 4 to the previous term. Nth term in this sequence equals 4n-2.

Given

per month salary in 11th year of service = rs 200

per month salary in 24th year of service = rs 495

Find

if the monthly salary is in ap then find the initial salary.

Solution

let the initial salary of the employee be Rs a and increment in his salary be Rs d.

from the given data we know  that his monthly salary is in AP.

also a₁₁ = 300 and a₂₄ = 495

therefore, a ₊ 10d = 300 ......eq(1)

                 a ₊ 23d = 495 ......eq(2)

subtract eq(1) from eq(2)

we get,

a ₊ 23d ₋ (a  10d) = 495 ₋₋ 300

13d = 195

d = 195/13

d = 15

hence, increment in his monthly salary is Rs 15.

substitute the value of d in eq(1), we get

a ₊ 150 = 300

a = 300 ₋ 150

a = 150

therefore employee's initial salary is Rs. 150

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