An employee, travelling at 20 km/h, reaches his
office half-an-hour late than the time he would
take while travelling at 25 km/h. Find the distance
between his house and the office.
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Answered by
10
Answer:
speed 1 × time 1 = speed 2×Tme 2
20× (x +1/2) =25x
20x+10 = 25x
10= 5x
x=2
Put x=2 in s1×t1
20×(2+1/2)
20×5/2
=50km
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2
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