Question

an empty bag weights 1 1/5 kg . If 4 5/8 kg of patatoes and 3 1/2 of tomatoes are kept in it , how much does it weight now?​

Answer 1

Answer:

500 grams

Step-by-step explanation:

ANSWER

Given that,

The ratio of tomatoes, potatoes and onions is 6:9:5 in gram

We know that,

1kg=1000g

∴ 2kg=2000g

Sum of the given ratio 6+9+5=20g

20g=2000

1g=100

Tomatoes =6×100=600g

potatoes =9×100=900g

And onions =5×100=500g

Answer 2

Weight of the empty bag ⇒ $\sf 1\frac{1}{5}\ kg$

Weight of potatoes ⇒ $\sf 4\frac{5}{8} \ kg$

Weight of the tomatoes ⇒ $\sf 3\frac{1}{2} \ kg$

Total weight of the bag ⇒ $\sf 1\frac{1}{5} + 4\frac{5}{8} + 3\frac{1}{2}$

To solve this we need to convert the mixed fractions into improper fractions.

To do so we need to multiply the whole number by the denominator part of the fractional part and add the product to the numerator part of the fractional part. The number we get will be the numerator of the improper fraction and the denominator will be the same as the denominator of the fractional part of the mixed fraction.

$\sf 1\frac{1}{5} = \frac{(1\times 5) +1}{5} = \frac{6}{5} \ kg$

$\sf 4\frac{5}{8} = \frac{(4\times 8)+5 }{8} = \frac{37}{8} \ kg$

$\sf 3\frac{1}{2} = \frac{(3\times 2)+1 }{2} = \frac{7}{2} \ kg$

Now we have to add ⇒ $\sf \frac{6}{5}+\frac{37}{8}+\frac{7}{2}$

First we need to find the LCM of the denominators.

$\begin{array}{r | l} 2 & 5,8,2\\ \cline{2-2} 2 & 5,4,1\\ \cline{2-2} 2& 5,2,1\\ \cline{2-2} 5 &5,1,1 \\ \cline{2-2} & 1,1,1\end{array}$

LCM ⇒ $\sf 2\times 2\times 2\times 5 = 40$

Now using the LCM we will make the denominators equal.

$\sf \frac{6\times 8}{5\times 8 }+\frac{37\times 5 }{8\times 5 }+\frac{7\times 20 }{2\times 20 }$

$\sf \frac{48}{40}+\frac{185}{40}+\frac{140}{40}$

To get the answer we need to add the numerator and let the denominator be the same.

$\sf \frac{48}{40}+\frac{185}{40}+\frac{140}{40}$

$\sf \frac{373}{40}$

$\sf 9\frac{13}{40}$

∴ The weight of the bag now would be $\bf 9\frac{13}{40}$.