An empty swimming pool can be filled to capacity through an inlet pipe in 3 hours, and it can be completely drained by a drain pipe in 6 hours. if both pipes are fully open at the same time, in how many hours will the empty pool be filled to capacity?
Answers
Answered by
24
Solution :-
In 3 hours the swimming pool can be filled to the capacity.
Then, in 1 hour the part of swimming pool can be filled = 1/3th part
And,
In 6 hours, the drain pipe completely drain the swimming pool
Then, in 1 hour, the drain pipe will completely drain the part of the swimming pool =
1/6th part
When both pipes are open,
⇒ 1/3 - 1/6 = 1/6
So, 1/6th of the swimming pool is filled in 1 hour.
Hence it will take 6 hours to completely fill the pool to capacity.
Answer.
In 3 hours the swimming pool can be filled to the capacity.
Then, in 1 hour the part of swimming pool can be filled = 1/3th part
And,
In 6 hours, the drain pipe completely drain the swimming pool
Then, in 1 hour, the drain pipe will completely drain the part of the swimming pool =
1/6th part
When both pipes are open,
⇒ 1/3 - 1/6 = 1/6
So, 1/6th of the swimming pool is filled in 1 hour.
Hence it will take 6 hours to completely fill the pool to capacity.
Answer.
Answered by
1
Answer:
Time taken by inlet pipe to fill = 3 hours
Volume filled in 1 hour =
Time taken by outlet pipe to empty = 6 hours
Volume emptied in 1 hour =
Amount of work done in an hour =
Therefore time taken (flipping the numerator and denominator) = 6 hours
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