An empty vial weighs 50.90 g. If the vial weighs 439.31 g when filled with liquid mercury (d = 13.53 g/cm^3), what volume of mercury is in the vial?
Answers
Answer:
28.71 cm
3
Explanation:
Your strategy here will be to use the mass of the empty vial and the mass of the vial when filled with mercury to find the mass of mercury added to the vial.
Once you know the mass of mercury, you can use its density to find the volume of mercury present in the vial, i.e. the volume of the vial.
So, you know that the vial + mercury has a mass of
vial
+
mercury
=
439.31 g
The mass of the vial is
vial
=
50.90 g
This means that the mass of the mercury will be
mercury
=
439.31 g
−
50.90 g
=
388.41 g
Now, you know that mercury has a density of
13.53 g/cm
3
. What this means is that
1 cm
3
of mercury has a mass of
13.53 g
.
In your case, the volume of the sample will be
388.41
g
⋅
1 cm
3
13.53
g
=
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
a
a
28.71 cm
3
a
a
∣
∣
−−−−−−−−−−−−