An engine and a train weight 200 metric tons and the engine can exert a pull of 5 metric tons wt. Find the tension in the coupling if the engine alone weights 60 metric tons, the resistance being equal to 10 kg per ton.
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Answer:
F=m*a
Engine force or thrust = total mass of coupled system times acceleration.
6000 Kg wt = (mass of engine + mass of carriage) * acceleration.
acceleration of the engine and carriage assembly = 6,000 kg-m/s^2 / (205 metric ton * 1000 kg/ metric ton) = 6/205 m/s^2.
The acceleration of the carriage is entirely due to the pull (tension) transferred through the coupling.
Again, F = ma,
so,
F = (mass of carriage * acceleration)
F = 205 kg * 6/205 m/s^2.
Resistance =10*205=2050
Resultant tension is = 6000-2050=3950
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