An engine driver moving towards a wall with velocity of 50m/s emits a note of frequcency1.5kHz. The frequency of note after reflection from the wall as hear by the engine driver when speed of sound in air is 350m/s is

Answers
Given :
velocity of air , v = 350 m/s
initial frequency , f = 1.5 kHz
velocity of train, vt = 50 m/s
To find :
Frequency observed by the driver after reflection from the wall.
Solution :
First we have to find the frequency observed at the wall. That frequency will be reflected. with the help of the new frequency we can find the observed frequency .
frequency observed at wall , fw = ( v * f ) / ( v - vt ) .........(i)
frequency observed by driver = ( v + vt ) * fw / v ..........(ii)
putting (i) in (ii) ,
frequency observed by driver = ( v + vt ) * f / ( v - vt )
= ( 400 / 300 ) * 1.5 kHz
= 2 kHz
The frequency observed by the driver after reflection is 2 kHz .