Question

An engine giving off whistle is moving towards a stationary observer with 50m/s speed. What will be the ratio of the frequencies of the whistle heard when engine is approaching and receding from the observer? (speed of sound = 350 m/s)

Answer 1

Answer:

When the source moves relative to a stationary observer. When the ... You hear a sound with a higher pitch. .... Take the speed of sound in air to yehh

Answer 2

Answer:

4/3

Explanation:F'=F[velocity of sound +or- velocity of observer]/[velocity of sound =or- velocity of source]

F1(approaching)= F*350/(350-50)                     F=original frequency

                             F*7/6                          

F2(receding)=F*350/(350+50)

                     =F*7/8

F1/F2 = 4/3

I hope this helps you