Physics, asked by samihayasmeen22, 11 months ago

An engine giving off whistle is moving towards
a stationary observer with 50m/s speed. What will
be the ratio of the frequencies of the whistle heard
when engine is approaching and receding from the
observer? (speed of sound = 350 m/s)

Answers

Answered by ashisgupta1972

0

Answer:

Explanation:

v=fλ

thus , λ is constant and f is also constant.

v1/v2=50/350=1:7

Answered by aravind10900

0

Answer:4/3

Explanation:see attachment

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