An engine giving off whistle is moving towards
a stationary observer with 50m/s speed. What will
be the ratio of the frequencies of the whistle heard
when engine is approaching and receding from the
observer? (speed of sound = 350 m/s)
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Answered by
0
Answer:
Explanation:
v=fλ
thus , λ is constant and f is also constant.
v1/v2=50/350=1:7
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Answer:4/3
Explanation:see attachment
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