An engine of 10 m length travels at 60 kmph. how long does it take to cross another train 170 m long, running at 54 kmph in the same direction
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Given :
Length of first engine=10m
Speed of first engine=60km/h
Speed of second enigne=54km/hr
length 0f second train=170m
Relative speed=60-54=6x18/5m/s[∵Travelling in same direction]
Distance=10+170=180m
Time=distance/speed
=180x5/6x18
=900/108=8.33 sec
∴It takes 8.3 sec to cross another train running at a speed of 54km/hr in same direction.
Length of first engine=10m
Speed of first engine=60km/h
Speed of second enigne=54km/hr
length 0f second train=170m
Relative speed=60-54=6x18/5m/s[∵Travelling in same direction]
Distance=10+170=180m
Time=distance/speed
=180x5/6x18
=900/108=8.33 sec
∴It takes 8.3 sec to cross another train running at a speed of 54km/hr in same direction.
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Solution -
Formula- Trains with speed v1 and v2 and if both the trains are moving in the same direction then,
[Length of the train 1 - Length of the train 2](m) = [Speed of the train 1 - Speed of the train 2](m/s) X Time taken to cross(s)
...........as (distance = speed * time)
[10 + 170] (m) = [60Kmph - 54Kmph] (m/s) X Time taken
180m = 6 X 5/18 X Time taken ------------(1Km/h = 5/18 m/s)
Time taken = (180 X 18) / (6 X 5) = 108 sec
Answer - The train take 108 sec to cross another train.
Formula- Trains with speed v1 and v2 and if both the trains are moving in the same direction then,
[Length of the train 1 - Length of the train 2](m) = [Speed of the train 1 - Speed of the train 2](m/s) X Time taken to cross(s)
...........as (distance = speed * time)
[10 + 170] (m) = [60Kmph - 54Kmph] (m/s) X Time taken
180m = 6 X 5/18 X Time taken ------------(1Km/h = 5/18 m/s)
Time taken = (180 X 18) / (6 X 5) = 108 sec
Answer - The train take 108 sec to cross another train.
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