Question

An engine operates between temperature limits of 900 k, t2 and another between t2 and 400 k. For both to be equally efficient, the value of t2 will be

Answer 1

1-Tl/Th is effeciency so we get t2^2:360000 so t2 is 600

Answer 2

efficient of engine is
$n = 1 - t \div t2$