Question

An engine provides 5000n of force to keep a 1600kg vehicle in a uniform speed (air resistance is negligible) what is co efficient ofrolling friction between the tiresans road surface

Answer 1

hlo mate here is ur ans..

Vehicle moving at a uniform speed therefore acceleration equals 0.

Assuming Newton’s first law of motion:- =

where is the friction force, is the force the engine.Force of friction equals:=

where is normal force, is weight of the vehicle.Coefficient of rolling friction equals:- =/

=/=5000/1600⋅9.8 = 0.32

hope this helps uh dear :)

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