Physics, asked by taneesha76, 3 months ago

An engine pumps up 200kg of water through a height of 20m in 20 sec. The efficiency of the engine is 50% , what is the power of the engine ? (g=10m/ second square) 

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Answers

Answered by ravitavisen
2

Output power = mgh

t

= 5s

500kg×10 s²m/×10m

=10×10³Watt

=10kW

Effeciency=[ (Inputpower) (Outputpower ]×100

75=[ (Inputpower)10kW ]×100

Inputpower=1.33kW

Answered by FrankFelix
0

Answer:

Above answer is correct.

Explanation:

Verified by me ;)

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