Question

An engineering student has to secure 40% marks to pass .he get 80 marks and fails by 40 marks.find maximum

Answer 1

Answer:

percentage of marks needed=40%

marks scored by him=80

marks needed to get favourable result=40

so, let the maximum marks be x.

As per the question,

40/100(x)=80+40

40/100(x)=120

x=120×100/40

therefore, x=300.

The maximum mark is 300.

Answer 2

Step-by-step explanation:

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