Question

An enzyme contain contain ,5.6 qfe calc Fe atom present in 1 g of enzymes? ​

Answer 1

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Answer 2

ᴀɴꜱᴡᴇʀ!!

Solution : Given,

An enzyme contains 5.6 % Fe that means, in 100 g of enzyme 5.6 g of Fe is present.

As, 100 g of enzyme contains 5.6 g of Fe

So, 1 g of enzyme contains g of Fe

Now we have to calculate the number of Fe atoms.

1 mole weighs 56 grams as contains number of ᴀᴛᴏᴍꜱ =0.056 ɢʀᴀᴍꜱ

As, 56 grams contains number of Fe ᴀᴛᴏᴍꜱ

So, 0.056 grams contains number of Fe ᴀᴛᴏᴍꜱ =0.056×6.022×10^23

Therefore, the number of Fe atoms present in 1 g of enzyme is, 6.022×10^20