an equilateral prism is made of glass of unknown refractive index.when a parallel beam of light is incident on a face of the prism the angle of minimum deviation is found to be 40°.calculate the refractive index of the material of prism.if the prism is placed in water of refractive index 1.33 ,find the new angle of minimum deviation of a parallel beam of light. (A*18)
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Answer:
The answer is 60°
Explanation:
Refractive index of a prism is given by the eq uation.
Refractive index = [Sin{A+DM}/2]/SinA/2
= Sin[{60+Dm}/2]/Sin(60/2)=√3
= Sin{30+(Dm/2)}/Sin30=√3
= Sin{30+(Dm/2)}×2=√3
= 30+(Dm/2)= Sin-1(√3/2)=60°= Dm/2 = 60°–30
Dm =30×2=60°
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