Question

An equilibrium system for the reaction between hydrogen and iodine to give hydrogen iodide at 765 k

Answer 1

Reaction will be given as:

H2 (g) + I2 (g) = 2 HI (g)

Therefore, the equilibrium constant K will be given as:

K = [HI] 2 / [H2] [I2]

The molar concentrations of the species at equilibrium are:

[H2] = 0.4 / 5 = 0.08 mol L-1

[I2] = 0.4 / 5 = 0.08 mol L-1

[HI] = 2.4 / 5 = 0.48 mol L-1

Substituting these values in the expression of K, we will get:

K = (0.48) 2 / (0.08) (0.08)

K = 36.0

Hence the equilibrium constant is equal to 36.0