Question

An examination is being held in and two parts and there 572 examinees in all 3/11 of total no of examinees appears in part I only and 3/13 appears in part 11 only the rest appear in both the part find the no of candidates appearing in both the part

Answer 1

71/143 and 284 candidates appearing in both the part

Answer 2

Answer:

284

Step-by-step explanation:

Let the number of candidates in both exam = x

according to the question,

Part 1

Total number of examiners = 572

3/11 of 572 = 52 * 3 = 156

Part 2

3/13 of total number of examiners = 3/13 * 572 = 3 * 44 = 132

Rest appeared in both exams (part 1 + part 2) =  572 - ( 132 + 156)

x =  572 - 288 = 284