Question

An examination is being held in two parts and there are 572 examinies in all.3/11 of the total number of examinies appears in part 1.only and 3/13 appears in part 2 only.the rest appear in both the parts .find the number of candidates appearing in both the part

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The number of candidates appearing in both the part is 284

Solution:

Given that,

Total examinees = 572

3/11 of the total number of examinies appears in part 1

Therefore,

$\text{Examinies in part 1 } = \frac{3}{11} \times 572 \\\\\text{Examinies in part 1 } = 156$

3/13 appears in part 2 only

Therefore,

$\text{Examinies in part 2} = \frac{3}{13} \times 572 \\\\\text{Examinies in part 2} =132$

The rest appear in both the parts

Find the number of candidates appearing in both the part

Appearing in both the part = 572 - 156 - 132

Appearing in both the part = 284

Thus number of candidates appearing in both the part is 284

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