Math, asked by hemuanshu7479, 1 year ago

an examinee is required to answer 6 questions out of 12 questions which are divided into two groups each containing six questions and he is not permitted to answer more than four questions from any group.in how many ways he can answer the 6 questions?; an examinee is required to answer 6 questions out of 12 questions which are divided into two groups each containing six questions and he is not permitted to answer more than four questions from any group.in how many ways he can answer the 6 questions?

Answers

Answered by Anonymous
3

Answer:

Heya ☺

Given that

x = 2 + √3

1/x = 1/2 + √3

= 1 × (2 - √3)/(2 + √3) (2 - √3)

= (2 - √3)/(2^2 - √3^2)

= (2 - √3)/4 - 3

= (2 - √3)

Therefore ,

x^2 = (2 + √3)

= (2)^2 + (√3)^2 + 2 × 2 × √3

= 4 + 3 + 4√3

= 7 + 4√3

1/x^2 = (2 - √3)^2

= (2)^2 + (√3)^2 - 2 × 2 × √3

= 4 + 3 - 4√3

= 7 - 4√3

x^2 + 1/x^2

= (7 + 4√3) + (7 - 4√3)

= 7 + 4√3 + 7 - 4√3

= 7 + 7 + 4√3 - 4√3

= 14

hope it helps you .....

mark as brainiest.......

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