Physics, asked by nirajrocki5471, 10 months ago

An excited he+ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength , energy 1240 ev
e.(in nm) )

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Answered by Abignya
1

Explanation:

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Answered by Anonymous
0

An excited he+ ion emits two photons in succession, with wavelengths 108.5 nm and 30.4 nm, in making a transition to ground state. The quantum number n, corresponding to its initial excited state is (for photon of wavelength , energy 1240 ev

e.(in nm) )

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