An experiment requires a gas with gama = 1.50. This can be achieved by mixing together monoatomic and rigid diatomic ideal gases. the ratio of moles of the monoatomic to diatomic gas in the mixture is ?
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Answer:
Explanation:
Let and be the number of moles of monoatomic and diatomic gases respectively
γ = where f is degrees of freedom
f' for a mixture of gases is given by where n stands for the number of moles of a particular gas
Since degrees of freedom of monoatomic gas (f1) and diatomic gas (f2) are 3 and 5 respectively;
f'=
∴
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