Question

An express train takes 1 hour less than a passenger train to travel 132 km between mysore and bangalore. if the average speed of the express train is 11 km per hour more than that of the passenger train find the average speech of the two trains.

Answer 1

see this answer...hope it will help you

Answer 2

hey friend!!!!


Let the speed of passenger train be x km/hr


Hence speed of express train = (x +11) km/hr

Distance travelled by both the trains = 132 km

Time taken = (Distance)/(Speed)

Time taken by the passenger train = 132/x hrs

Time taken by the express train = 132/(x + 11) hrs

hence

=> (132/x) - (132/(x+11)) = 1

=> 132(x+11-x) /(x×(x+11)) = 1

⇒132 × 11 = x(x + 11)

⇒x2+ 11x – 1452 = 0

⇒x2+ 44x – 33x – 1452 = 0

⇒x(x + 44) – 33(x + 44) = 0

⇒(x + 44)(x – 33) = 0

⇒(x + 44) = 0 or (x – 33) = 0

∴ x = –44 or x = 33

Since speed cannot be negative, x = 33
Thus the sped of passenger train is 33 km/hr and speed of express train is 44 km/hr.


hope it will help you..