Question

An express train takes 1 hour less than a passenger train to travel 132 km between mysore and Bangalore. If the average speed of the express train is 11 km per hr more than that of the passenger train, form the quadratic equation to find the average speed of express train

Answer 1

Here is your answer

Answer 2

Answer:

The speed of the express train is 44 Km/hr.

Step-by-step explanation:

Let the speed of the passenger train be x.

And its given that the speed of express train is 11km/hr more than the passenger train.

Therefore the speed of the express train be x+11.

The distance to be travelled is 132 Km.

Now we know time=distance/speed.

Now from the equation we get that passenger train takes more time than express train.

The equation becomes -

132/x-132/x+11=1

x^2+11x-1452=0

x^2+44x-33x-1452=0

x(x+44) -33(x+44)

(x-33) (x+44)

x=33, -44

But speed can't be negative therefore speed of the passenger train is 33kmph.

Therefore, the speed of the express train is 44kmph.

I hope my answer helped you, please mark my answer the brainliest.

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Thank you.