An express train takes 30 minutes less to cover a distance of 440 km, if its speed is increased by 8 km than its usual speed. What is the usual speed of the train?
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Let the average speed of passenger train be x km/h.
Average speed of express train = (x the same distance.
⇒ 132 × 11 = x(x + 11)
⇒ x2 + 11x - 1452 = 0
⇒ x2 + 44x -33x -1452 = 0
⇒ x(x + 44) -33(x + 44) = 0
⇒ (x + 44)(x - 33) = 0
⇒ x = - 44, 33
Speed cannot be negative.
Therefore, the speed of the passenger train will be 33 km/h and thus, the speed of the express train will be 33 + 11 = 44 km/h.
+ 11) km/h
It is given that the time taken by the express train to cover 132 km is 1 hour less than the passenger train to cover
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