an exterior angle of a triangle is 108 degree and its two interior opposite angles are equal find each of these equal angles
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let the angles be x
then 2x=108
x=108÷2
x=54
so the angles 54 each
then 2x=108
x=108÷2
x=54
so the angles 54 each
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Answer:
let the angles be X
then 2x=108
X=108 Devide 2
X=54
so the angle 54 each ☺️
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