An exterior angle of a triangle is 110° and one of the interior opposite angle is 30°.find the other two angles of the triangle.
Answers
Answered by
153
We know that the sum of the two interior angles of a triangle is equal to the opposite exterior angle.
One of the angles is 30°
The exterior angle is 110°
Let the other unknown angle be = x
30°+ x = 110°
x = 110°-30°
x=80°
The other angle of the triangle is 80°.
HOPE THIS HELPS YOU..................
:)
One of the angles is 30°
The exterior angle is 110°
Let the other unknown angle be = x
30°+ x = 110°
x = 110°-30°
x=80°
The other angle of the triangle is 80°.
HOPE THIS HELPS YOU..................
:)
Answered by
99
In the diagram, PQR is a Triangle.
∴ ∠a + 110° = 180° ❪Linear pair❫
⇒ ∠a = 180° - 110°
⇒ ∠a = 70°
Hence, ∠a = 70°.
∴ ∠P + ∠Q + ∠R = 180°
❪Sum of ∠s of a Triangle = 180°❫
⇒ ∠P + 30° + ∠a = 180°
⇒ ∠P + 30° + 70° = 180°
⇒ ∠P + 100° = 180°
⇒ ∠P = 180° - 100°
⇒ ∠P = 80°
Hence, ∠P = 80°.
Therefore, the other two angles of the triangle are 70° and 80°.
Hope it helps ツ
∴ ∠a + 110° = 180° ❪Linear pair❫
⇒ ∠a = 180° - 110°
⇒ ∠a = 70°
Hence, ∠a = 70°.
∴ ∠P + ∠Q + ∠R = 180°
❪Sum of ∠s of a Triangle = 180°❫
⇒ ∠P + 30° + ∠a = 180°
⇒ ∠P + 30° + 70° = 180°
⇒ ∠P + 100° = 180°
⇒ ∠P = 180° - 100°
⇒ ∠P = 80°
Hence, ∠P = 80°.
Therefore, the other two angles of the triangle are 70° and 80°.
Hope it helps ツ
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