Question

an exterior angle of triangle is 108 and its two interior opposite angles are equal. find each of these equal angles

Answer 1

each angle is 54degree
exterior angle=sum of two interior opposite angles
so, 108°=x°+x°
108°=2x°
108°/2°=x°
54°=X
here X represents the angle which we have to find.
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Answer 2

Hola


Answer ---

Let the equal angles be x

so, x + x = 108°

By the exterior angle thereom which yells us that the sum of two interior angles in equal to the exterior angle.


so, 2x = 108
x = 108/2
= 54°

thus, the two equal angles are

54°


Hope it helps you!